\(\int (f x)^m (d-c^2 d x^2)^3 (a+b \text {arccosh}(c x)) \, dx\) [145]

   Optimal result
   Rubi [A] (verified)
   Mathematica [A] (verified)
   Maple [F]
   Fricas [F]
   Sympy [F(-1)]
   Maxima [F]
   Giac [F(-2)]
   Mupad [F(-1)]

Optimal result

Integrand size = 27, antiderivative size = 429 \[ \int (f x)^m \left (d-c^2 d x^2\right )^3 (a+b \text {arccosh}(c x)) \, dx=-\frac {b c d^3 \left (2271+1329 m+284 m^2+27 m^3+m^4\right ) (f x)^{2+m} \left (1-c^2 x^2\right )}{f^2 (3+m)^2 (5+m)^2 (7+m)^2 \sqrt {-1+c x} \sqrt {1+c x}}+\frac {b c^3 d^3 (9+m) (13+2 m) (f x)^{4+m} \left (1-c^2 x^2\right )}{f^4 (5+m)^2 (7+m)^2 \sqrt {-1+c x} \sqrt {1+c x}}-\frac {b c^5 d^3 (f x)^{6+m} \left (1-c^2 x^2\right )}{f^6 (7+m)^2 \sqrt {-1+c x} \sqrt {1+c x}}+\frac {d^3 (f x)^{1+m} (a+b \text {arccosh}(c x))}{f (1+m)}-\frac {3 c^2 d^3 (f x)^{3+m} (a+b \text {arccosh}(c x))}{f^3 (3+m)}+\frac {3 c^4 d^3 (f x)^{5+m} (a+b \text {arccosh}(c x))}{f^5 (5+m)}-\frac {c^6 d^3 (f x)^{7+m} (a+b \text {arccosh}(c x))}{f^7 (7+m)}-\frac {3 b c d^3 \left (2161+1813 m+455 m^2+35 m^3\right ) (f x)^{2+m} \sqrt {1-c^2 x^2} \operatorname {Hypergeometric2F1}\left (\frac {1}{2},\frac {2+m}{2},\frac {4+m}{2},c^2 x^2\right )}{f^2 (1+m) (2+m) (3+m)^2 (5+m)^2 (7+m)^2 \sqrt {-1+c x} \sqrt {1+c x}} \]

[Out]

d^3*(f*x)^(1+m)*(a+b*arccosh(c*x))/f/(1+m)-3*c^2*d^3*(f*x)^(3+m)*(a+b*arccosh(c*x))/f^3/(3+m)+3*c^4*d^3*(f*x)^
(5+m)*(a+b*arccosh(c*x))/f^5/(5+m)-c^6*d^3*(f*x)^(7+m)*(a+b*arccosh(c*x))/f^7/(7+m)-b*c*d^3*(m^4+27*m^3+284*m^
2+1329*m+2271)*(f*x)^(2+m)*(-c^2*x^2+1)/f^2/(7+m)^2/(m^2+8*m+15)^2/(c*x-1)^(1/2)/(c*x+1)^(1/2)+b*c^3*d^3*(9+m)
*(13+2*m)*(f*x)^(4+m)*(-c^2*x^2+1)/f^4/(5+m)^2/(7+m)^2/(c*x-1)^(1/2)/(c*x+1)^(1/2)-b*c^5*d^3*(f*x)^(6+m)*(-c^2
*x^2+1)/f^6/(7+m)^2/(c*x-1)^(1/2)/(c*x+1)^(1/2)-3*b*c*d^3*(35*m^3+455*m^2+1813*m+2161)*(f*x)^(2+m)*hypergeom([
1/2, 1+1/2*m],[2+1/2*m],c^2*x^2)*(-c^2*x^2+1)^(1/2)/f^2/(7+m)^2/(m^2+3*m+2)/(m^2+8*m+15)^2/(c*x-1)^(1/2)/(c*x+
1)^(1/2)

Rubi [A] (verified)

Time = 1.71 (sec) , antiderivative size = 429, normalized size of antiderivative = 1.00, number of steps used = 8, number of rules used = 9, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.333, Rules used = {276, 5921, 12, 1624, 1823, 1281, 470, 372, 371} \[ \int (f x)^m \left (d-c^2 d x^2\right )^3 (a+b \text {arccosh}(c x)) \, dx=-\frac {c^6 d^3 (f x)^{m+7} (a+b \text {arccosh}(c x))}{f^7 (m+7)}+\frac {3 c^4 d^3 (f x)^{m+5} (a+b \text {arccosh}(c x))}{f^5 (m+5)}-\frac {3 c^2 d^3 (f x)^{m+3} (a+b \text {arccosh}(c x))}{f^3 (m+3)}+\frac {d^3 (f x)^{m+1} (a+b \text {arccosh}(c x))}{f (m+1)}-\frac {3 b c d^3 \left (35 m^3+455 m^2+1813 m+2161\right ) \sqrt {1-c^2 x^2} (f x)^{m+2} \operatorname {Hypergeometric2F1}\left (\frac {1}{2},\frac {m+2}{2},\frac {m+4}{2},c^2 x^2\right )}{f^2 (m+1) (m+2) (m+3)^2 (m+5)^2 (m+7)^2 \sqrt {c x-1} \sqrt {c x+1}}-\frac {b c d^3 \left (m^4+27 m^3+284 m^2+1329 m+2271\right ) \left (1-c^2 x^2\right ) (f x)^{m+2}}{f^2 (m+3)^2 (m+5)^2 (m+7)^2 \sqrt {c x-1} \sqrt {c x+1}}-\frac {b c^5 d^3 \left (1-c^2 x^2\right ) (f x)^{m+6}}{f^6 (m+7)^2 \sqrt {c x-1} \sqrt {c x+1}}+\frac {b c^3 d^3 (m+9) (2 m+13) \left (1-c^2 x^2\right ) (f x)^{m+4}}{f^4 (m+5)^2 (m+7)^2 \sqrt {c x-1} \sqrt {c x+1}} \]

[In]

Int[(f*x)^m*(d - c^2*d*x^2)^3*(a + b*ArcCosh[c*x]),x]

[Out]

-((b*c*d^3*(2271 + 1329*m + 284*m^2 + 27*m^3 + m^4)*(f*x)^(2 + m)*(1 - c^2*x^2))/(f^2*(3 + m)^2*(5 + m)^2*(7 +
 m)^2*Sqrt[-1 + c*x]*Sqrt[1 + c*x])) + (b*c^3*d^3*(9 + m)*(13 + 2*m)*(f*x)^(4 + m)*(1 - c^2*x^2))/(f^4*(5 + m)
^2*(7 + m)^2*Sqrt[-1 + c*x]*Sqrt[1 + c*x]) - (b*c^5*d^3*(f*x)^(6 + m)*(1 - c^2*x^2))/(f^6*(7 + m)^2*Sqrt[-1 +
c*x]*Sqrt[1 + c*x]) + (d^3*(f*x)^(1 + m)*(a + b*ArcCosh[c*x]))/(f*(1 + m)) - (3*c^2*d^3*(f*x)^(3 + m)*(a + b*A
rcCosh[c*x]))/(f^3*(3 + m)) + (3*c^4*d^3*(f*x)^(5 + m)*(a + b*ArcCosh[c*x]))/(f^5*(5 + m)) - (c^6*d^3*(f*x)^(7
 + m)*(a + b*ArcCosh[c*x]))/(f^7*(7 + m)) - (3*b*c*d^3*(2161 + 1813*m + 455*m^2 + 35*m^3)*(f*x)^(2 + m)*Sqrt[1
 - c^2*x^2]*Hypergeometric2F1[1/2, (2 + m)/2, (4 + m)/2, c^2*x^2])/(f^2*(1 + m)*(2 + m)*(3 + m)^2*(5 + m)^2*(7
 + m)^2*Sqrt[-1 + c*x]*Sqrt[1 + c*x])

Rule 12

Int[(a_)*(u_), x_Symbol] :> Dist[a, Int[u, x], x] /; FreeQ[a, x] &&  !MatchQ[u, (b_)*(v_) /; FreeQ[b, x]]

Rule 276

Int[((c_.)*(x_))^(m_.)*((a_) + (b_.)*(x_)^(n_))^(p_.), x_Symbol] :> Int[ExpandIntegrand[(c*x)^m*(a + b*x^n)^p,
 x], x] /; FreeQ[{a, b, c, m, n}, x] && IGtQ[p, 0]

Rule 371

Int[((c_.)*(x_))^(m_.)*((a_) + (b_.)*(x_)^(n_))^(p_), x_Symbol] :> Simp[a^p*((c*x)^(m + 1)/(c*(m + 1)))*Hyperg
eometric2F1[-p, (m + 1)/n, (m + 1)/n + 1, (-b)*(x^n/a)], x] /; FreeQ[{a, b, c, m, n, p}, x] &&  !IGtQ[p, 0] &&
 (ILtQ[p, 0] || GtQ[a, 0])

Rule 372

Int[((c_.)*(x_))^(m_.)*((a_) + (b_.)*(x_)^(n_))^(p_), x_Symbol] :> Dist[a^IntPart[p]*((a + b*x^n)^FracPart[p]/
(1 + b*(x^n/a))^FracPart[p]), Int[(c*x)^m*(1 + b*(x^n/a))^p, x], x] /; FreeQ[{a, b, c, m, n, p}, x] &&  !IGtQ[
p, 0] &&  !(ILtQ[p, 0] || GtQ[a, 0])

Rule 470

Int[((e_.)*(x_))^(m_.)*((a_) + (b_.)*(x_)^(n_))^(p_.)*((c_) + (d_.)*(x_)^(n_)), x_Symbol] :> Simp[d*(e*x)^(m +
 1)*((a + b*x^n)^(p + 1)/(b*e*(m + n*(p + 1) + 1))), x] - Dist[(a*d*(m + 1) - b*c*(m + n*(p + 1) + 1))/(b*(m +
 n*(p + 1) + 1)), Int[(e*x)^m*(a + b*x^n)^p, x], x] /; FreeQ[{a, b, c, d, e, m, n, p}, x] && NeQ[b*c - a*d, 0]
 && NeQ[m + n*(p + 1) + 1, 0]

Rule 1281

Int[((f_.)*(x_))^(m_.)*((d_) + (e_.)*(x_)^2)^(q_.)*((a_) + (b_.)*(x_)^2 + (c_.)*(x_)^4)^(p_.), x_Symbol] :> Si
mp[c^p*(f*x)^(m + 4*p - 1)*((d + e*x^2)^(q + 1)/(e*f^(4*p - 1)*(m + 4*p + 2*q + 1))), x] + Dist[1/(e*(m + 4*p
+ 2*q + 1)), Int[(f*x)^m*(d + e*x^2)^q*ExpandToSum[e*(m + 4*p + 2*q + 1)*((a + b*x^2 + c*x^4)^p - c^p*x^(4*p))
 - d*c^p*(m + 4*p - 1)*x^(4*p - 2), x], x], x] /; FreeQ[{a, b, c, d, e, f, m, q}, x] && NeQ[b^2 - 4*a*c, 0] &&
 IGtQ[p, 0] &&  !IntegerQ[q] && NeQ[m + 4*p + 2*q + 1, 0]

Rule 1624

Int[(Px_)*((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_)*((e_.) + (f_.)*(x_))^(p_.), x_Symbol] :> Dist[(a
 + b*x)^FracPart[m]*((c + d*x)^FracPart[m]/(a*c + b*d*x^2)^FracPart[m]), Int[Px*(a*c + b*d*x^2)^m*(e + f*x)^p,
 x], x] /; FreeQ[{a, b, c, d, e, f, m, n, p}, x] && PolyQ[Px, x] && EqQ[b*c + a*d, 0] && EqQ[m, n] &&  !Intege
rQ[m]

Rule 1823

Int[(Pq_)*((c_.)*(x_))^(m_.)*((a_) + (b_.)*(x_)^2)^(p_), x_Symbol] :> With[{q = Expon[Pq, x], f = Coeff[Pq, x,
 Expon[Pq, x]]}, Simp[f*(c*x)^(m + q - 1)*((a + b*x^2)^(p + 1)/(b*c^(q - 1)*(m + q + 2*p + 1))), x] + Dist[1/(
b*(m + q + 2*p + 1)), Int[(c*x)^m*(a + b*x^2)^p*ExpandToSum[b*(m + q + 2*p + 1)*Pq - b*f*(m + q + 2*p + 1)*x^q
 - a*f*(m + q - 1)*x^(q - 2), x], x], x] /; GtQ[q, 1] && NeQ[m + q + 2*p + 1, 0]] /; FreeQ[{a, b, c, m, p}, x]
 && PolyQ[Pq, x] && ( !IGtQ[m, 0] || IGtQ[p + 1/2, -1])

Rule 5921

Int[((a_.) + ArcCosh[(c_.)*(x_)]*(b_.))*((f_.)*(x_))^(m_)*((d_) + (e_.)*(x_)^2)^(p_.), x_Symbol] :> With[{u =
IntHide[(f*x)^m*(d + e*x^2)^p, x]}, Dist[a + b*ArcCosh[c*x], u, x] - Dist[b*c, Int[SimplifyIntegrand[u/(Sqrt[1
 + c*x]*Sqrt[-1 + c*x]), x], x], x]] /; FreeQ[{a, b, c, d, e, f, m}, x] && EqQ[c^2*d + e, 0] && IGtQ[p, 0]

Rubi steps \begin{align*} \text {integral}& = \frac {d^3 (f x)^{1+m} (a+b \text {arccosh}(c x))}{f (1+m)}-\frac {3 c^2 d^3 (f x)^{3+m} (a+b \text {arccosh}(c x))}{f^3 (3+m)}+\frac {3 c^4 d^3 (f x)^{5+m} (a+b \text {arccosh}(c x))}{f^5 (5+m)}-\frac {c^6 d^3 (f x)^{7+m} (a+b \text {arccosh}(c x))}{f^7 (7+m)}-(b c) \int \frac {d^3 (f x)^{1+m} \left (\frac {1}{1+m}-\frac {3 c^2 x^2}{3+m}+\frac {3 c^4 x^4}{5+m}-\frac {c^6 x^6}{7+m}\right )}{f \sqrt {-1+c x} \sqrt {1+c x}} \, dx \\ & = \frac {d^3 (f x)^{1+m} (a+b \text {arccosh}(c x))}{f (1+m)}-\frac {3 c^2 d^3 (f x)^{3+m} (a+b \text {arccosh}(c x))}{f^3 (3+m)}+\frac {3 c^4 d^3 (f x)^{5+m} (a+b \text {arccosh}(c x))}{f^5 (5+m)}-\frac {c^6 d^3 (f x)^{7+m} (a+b \text {arccosh}(c x))}{f^7 (7+m)}-\frac {\left (b c d^3\right ) \int \frac {(f x)^{1+m} \left (\frac {1}{1+m}-\frac {3 c^2 x^2}{3+m}+\frac {3 c^4 x^4}{5+m}-\frac {c^6 x^6}{7+m}\right )}{\sqrt {-1+c x} \sqrt {1+c x}} \, dx}{f} \\ & = \frac {d^3 (f x)^{1+m} (a+b \text {arccosh}(c x))}{f (1+m)}-\frac {3 c^2 d^3 (f x)^{3+m} (a+b \text {arccosh}(c x))}{f^3 (3+m)}+\frac {3 c^4 d^3 (f x)^{5+m} (a+b \text {arccosh}(c x))}{f^5 (5+m)}-\frac {c^6 d^3 (f x)^{7+m} (a+b \text {arccosh}(c x))}{f^7 (7+m)}-\frac {\left (b c d^3 \sqrt {-1+c^2 x^2}\right ) \int \frac {(f x)^{1+m} \left (\frac {1}{1+m}-\frac {3 c^2 x^2}{3+m}+\frac {3 c^4 x^4}{5+m}-\frac {c^6 x^6}{7+m}\right )}{\sqrt {-1+c^2 x^2}} \, dx}{f \sqrt {-1+c x} \sqrt {1+c x}} \\ & = -\frac {b c^5 d^3 (f x)^{6+m} \left (1-c^2 x^2\right )}{f^6 (7+m)^2 \sqrt {-1+c x} \sqrt {1+c x}}+\frac {d^3 (f x)^{1+m} (a+b \text {arccosh}(c x))}{f (1+m)}-\frac {3 c^2 d^3 (f x)^{3+m} (a+b \text {arccosh}(c x))}{f^3 (3+m)}+\frac {3 c^4 d^3 (f x)^{5+m} (a+b \text {arccosh}(c x))}{f^5 (5+m)}-\frac {c^6 d^3 (f x)^{7+m} (a+b \text {arccosh}(c x))}{f^7 (7+m)}-\frac {\left (b d^3 \sqrt {-1+c^2 x^2}\right ) \int \frac {(f x)^{1+m} \left (\frac {c^2 (7+m)}{1+m}-\frac {3 c^4 (7+m) x^2}{3+m}+\frac {c^6 (9+m) (13+2 m) x^4}{(5+m) (7+m)}\right )}{\sqrt {-1+c^2 x^2}} \, dx}{c f (7+m) \sqrt {-1+c x} \sqrt {1+c x}} \\ & = \frac {b c^3 d^3 (9+m) (13+2 m) (f x)^{4+m} \left (1-c^2 x^2\right )}{f^4 (5+m)^2 (7+m)^2 \sqrt {-1+c x} \sqrt {1+c x}}-\frac {b c^5 d^3 (f x)^{6+m} \left (1-c^2 x^2\right )}{f^6 (7+m)^2 \sqrt {-1+c x} \sqrt {1+c x}}+\frac {d^3 (f x)^{1+m} (a+b \text {arccosh}(c x))}{f (1+m)}-\frac {3 c^2 d^3 (f x)^{3+m} (a+b \text {arccosh}(c x))}{f^3 (3+m)}+\frac {3 c^4 d^3 (f x)^{5+m} (a+b \text {arccosh}(c x))}{f^5 (5+m)}-\frac {c^6 d^3 (f x)^{7+m} (a+b \text {arccosh}(c x))}{f^7 (7+m)}-\frac {\left (b d^3 \sqrt {-1+c^2 x^2}\right ) \int \frac {(f x)^{1+m} \left (\frac {c^4 (5+m) (7+m)}{1+m}-\frac {c^6 \left (2271+1329 m+284 m^2+27 m^3+m^4\right ) x^2}{(3+m) (5+m) (7+m)}\right )}{\sqrt {-1+c^2 x^2}} \, dx}{c^3 f (5+m) (7+m) \sqrt {-1+c x} \sqrt {1+c x}} \\ & = -\frac {b c d^3 \left (2271+1329 m+284 m^2+27 m^3+m^4\right ) (f x)^{2+m} \left (1-c^2 x^2\right )}{f^2 (3+m)^2 (5+m)^2 (7+m)^2 \sqrt {-1+c x} \sqrt {1+c x}}+\frac {b c^3 d^3 (9+m) (13+2 m) (f x)^{4+m} \left (1-c^2 x^2\right )}{f^4 (5+m)^2 (7+m)^2 \sqrt {-1+c x} \sqrt {1+c x}}-\frac {b c^5 d^3 (f x)^{6+m} \left (1-c^2 x^2\right )}{f^6 (7+m)^2 \sqrt {-1+c x} \sqrt {1+c x}}+\frac {d^3 (f x)^{1+m} (a+b \text {arccosh}(c x))}{f (1+m)}-\frac {3 c^2 d^3 (f x)^{3+m} (a+b \text {arccosh}(c x))}{f^3 (3+m)}+\frac {3 c^4 d^3 (f x)^{5+m} (a+b \text {arccosh}(c x))}{f^5 (5+m)}-\frac {c^6 d^3 (f x)^{7+m} (a+b \text {arccosh}(c x))}{f^7 (7+m)}-\frac {\left (3 b c d^3 \left (2161+1813 m+455 m^2+35 m^3\right ) \sqrt {-1+c^2 x^2}\right ) \int \frac {(f x)^{1+m}}{\sqrt {-1+c^2 x^2}} \, dx}{f (1+m) (3+m)^2 (5+m)^2 (7+m)^2 \sqrt {-1+c x} \sqrt {1+c x}} \\ & = -\frac {b c d^3 \left (2271+1329 m+284 m^2+27 m^3+m^4\right ) (f x)^{2+m} \left (1-c^2 x^2\right )}{f^2 (3+m)^2 (5+m)^2 (7+m)^2 \sqrt {-1+c x} \sqrt {1+c x}}+\frac {b c^3 d^3 (9+m) (13+2 m) (f x)^{4+m} \left (1-c^2 x^2\right )}{f^4 (5+m)^2 (7+m)^2 \sqrt {-1+c x} \sqrt {1+c x}}-\frac {b c^5 d^3 (f x)^{6+m} \left (1-c^2 x^2\right )}{f^6 (7+m)^2 \sqrt {-1+c x} \sqrt {1+c x}}+\frac {d^3 (f x)^{1+m} (a+b \text {arccosh}(c x))}{f (1+m)}-\frac {3 c^2 d^3 (f x)^{3+m} (a+b \text {arccosh}(c x))}{f^3 (3+m)}+\frac {3 c^4 d^3 (f x)^{5+m} (a+b \text {arccosh}(c x))}{f^5 (5+m)}-\frac {c^6 d^3 (f x)^{7+m} (a+b \text {arccosh}(c x))}{f^7 (7+m)}-\frac {\left (3 b c d^3 \left (2161+1813 m+455 m^2+35 m^3\right ) \sqrt {1-c^2 x^2}\right ) \int \frac {(f x)^{1+m}}{\sqrt {1-c^2 x^2}} \, dx}{f (1+m) (3+m)^2 (5+m)^2 (7+m)^2 \sqrt {-1+c x} \sqrt {1+c x}} \\ & = -\frac {b c d^3 \left (2271+1329 m+284 m^2+27 m^3+m^4\right ) (f x)^{2+m} \left (1-c^2 x^2\right )}{f^2 (3+m)^2 (5+m)^2 (7+m)^2 \sqrt {-1+c x} \sqrt {1+c x}}+\frac {b c^3 d^3 (9+m) (13+2 m) (f x)^{4+m} \left (1-c^2 x^2\right )}{f^4 (5+m)^2 (7+m)^2 \sqrt {-1+c x} \sqrt {1+c x}}-\frac {b c^5 d^3 (f x)^{6+m} \left (1-c^2 x^2\right )}{f^6 (7+m)^2 \sqrt {-1+c x} \sqrt {1+c x}}+\frac {d^3 (f x)^{1+m} (a+b \text {arccosh}(c x))}{f (1+m)}-\frac {3 c^2 d^3 (f x)^{3+m} (a+b \text {arccosh}(c x))}{f^3 (3+m)}+\frac {3 c^4 d^3 (f x)^{5+m} (a+b \text {arccosh}(c x))}{f^5 (5+m)}-\frac {c^6 d^3 (f x)^{7+m} (a+b \text {arccosh}(c x))}{f^7 (7+m)}-\frac {3 b c d^3 \left (2161+1813 m+455 m^2+35 m^3\right ) (f x)^{2+m} \sqrt {1-c^2 x^2} \operatorname {Hypergeometric2F1}\left (\frac {1}{2},\frac {2+m}{2},\frac {4+m}{2},c^2 x^2\right )}{f^2 (1+m) (2+m) (3+m)^2 (5+m)^2 (7+m)^2 \sqrt {-1+c x} \sqrt {1+c x}} \\ \end{align*}

Mathematica [A] (verified)

Time = 0.79 (sec) , antiderivative size = 387, normalized size of antiderivative = 0.90 \[ \int (f x)^m \left (d-c^2 d x^2\right )^3 (a+b \text {arccosh}(c x)) \, dx=d^3 x (f x)^m \left (\frac {a+b \text {arccosh}(c x)}{1+m}-\frac {3 c^2 x^2 (a+b \text {arccosh}(c x))}{3+m}+\frac {3 c^4 x^4 (a+b \text {arccosh}(c x))}{5+m}-\frac {c^6 x^6 (a+b \text {arccosh}(c x))}{7+m}+\frac {b c^7 x^7 \sqrt {1-c^2 x^2} \operatorname {Hypergeometric2F1}\left (\frac {1}{2},4+\frac {m}{2},5+\frac {m}{2},c^2 x^2\right )}{(7+m) (8+m) \sqrt {-1+c x} \sqrt {1+c x}}-\frac {b c x \sqrt {1-c^2 x^2} \operatorname {Hypergeometric2F1}\left (\frac {1}{2},\frac {2+m}{2},\frac {4+m}{2},c^2 x^2\right )}{\left (2+3 m+m^2\right ) \sqrt {-1+c x} \sqrt {1+c x}}+\frac {3 b c^3 x^3 \sqrt {1-c^2 x^2} \operatorname {Hypergeometric2F1}\left (\frac {1}{2},\frac {4+m}{2},\frac {6+m}{2},c^2 x^2\right )}{\left (12+7 m+m^2\right ) \sqrt {-1+c x} \sqrt {1+c x}}-\frac {3 b c^5 x^5 \sqrt {1-c^2 x^2} \operatorname {Hypergeometric2F1}\left (\frac {1}{2},\frac {6+m}{2},\frac {8+m}{2},c^2 x^2\right )}{(5+m) (6+m) \sqrt {-1+c x} \sqrt {1+c x}}\right ) \]

[In]

Integrate[(f*x)^m*(d - c^2*d*x^2)^3*(a + b*ArcCosh[c*x]),x]

[Out]

d^3*x*(f*x)^m*((a + b*ArcCosh[c*x])/(1 + m) - (3*c^2*x^2*(a + b*ArcCosh[c*x]))/(3 + m) + (3*c^4*x^4*(a + b*Arc
Cosh[c*x]))/(5 + m) - (c^6*x^6*(a + b*ArcCosh[c*x]))/(7 + m) + (b*c^7*x^7*Sqrt[1 - c^2*x^2]*Hypergeometric2F1[
1/2, 4 + m/2, 5 + m/2, c^2*x^2])/((7 + m)*(8 + m)*Sqrt[-1 + c*x]*Sqrt[1 + c*x]) - (b*c*x*Sqrt[1 - c^2*x^2]*Hyp
ergeometric2F1[1/2, (2 + m)/2, (4 + m)/2, c^2*x^2])/((2 + 3*m + m^2)*Sqrt[-1 + c*x]*Sqrt[1 + c*x]) + (3*b*c^3*
x^3*Sqrt[1 - c^2*x^2]*Hypergeometric2F1[1/2, (4 + m)/2, (6 + m)/2, c^2*x^2])/((12 + 7*m + m^2)*Sqrt[-1 + c*x]*
Sqrt[1 + c*x]) - (3*b*c^5*x^5*Sqrt[1 - c^2*x^2]*Hypergeometric2F1[1/2, (6 + m)/2, (8 + m)/2, c^2*x^2])/((5 + m
)*(6 + m)*Sqrt[-1 + c*x]*Sqrt[1 + c*x]))

Maple [F]

\[\int \left (f x \right )^{m} \left (-c^{2} d \,x^{2}+d \right )^{3} \left (a +b \,\operatorname {arccosh}\left (c x \right )\right )d x\]

[In]

int((f*x)^m*(-c^2*d*x^2+d)^3*(a+b*arccosh(c*x)),x)

[Out]

int((f*x)^m*(-c^2*d*x^2+d)^3*(a+b*arccosh(c*x)),x)

Fricas [F]

\[ \int (f x)^m \left (d-c^2 d x^2\right )^3 (a+b \text {arccosh}(c x)) \, dx=\int { -{\left (c^{2} d x^{2} - d\right )}^{3} {\left (b \operatorname {arcosh}\left (c x\right ) + a\right )} \left (f x\right )^{m} \,d x } \]

[In]

integrate((f*x)^m*(-c^2*d*x^2+d)^3*(a+b*arccosh(c*x)),x, algorithm="fricas")

[Out]

integral(-(a*c^6*d^3*x^6 - 3*a*c^4*d^3*x^4 + 3*a*c^2*d^3*x^2 - a*d^3 + (b*c^6*d^3*x^6 - 3*b*c^4*d^3*x^4 + 3*b*
c^2*d^3*x^2 - b*d^3)*arccosh(c*x))*(f*x)^m, x)

Sympy [F(-1)]

Timed out. \[ \int (f x)^m \left (d-c^2 d x^2\right )^3 (a+b \text {arccosh}(c x)) \, dx=\text {Timed out} \]

[In]

integrate((f*x)**m*(-c**2*d*x**2+d)**3*(a+b*acosh(c*x)),x)

[Out]

Timed out

Maxima [F]

\[ \int (f x)^m \left (d-c^2 d x^2\right )^3 (a+b \text {arccosh}(c x)) \, dx=\int { -{\left (c^{2} d x^{2} - d\right )}^{3} {\left (b \operatorname {arcosh}\left (c x\right ) + a\right )} \left (f x\right )^{m} \,d x } \]

[In]

integrate((f*x)^m*(-c^2*d*x^2+d)^3*(a+b*arccosh(c*x)),x, algorithm="maxima")

[Out]

-a*c^6*d^3*f^m*x^7*x^m/(m + 7) + 3*a*c^4*d^3*f^m*x^5*x^m/(m + 5) - 3*a*c^2*d^3*f^m*x^3*x^m/(m + 3) + (f*x)^(m
+ 1)*a*d^3/(f*(m + 1)) - ((m^3 + 9*m^2 + 23*m + 15)*b*c^6*d^3*f^m*x^7 - 3*(m^3 + 11*m^2 + 31*m + 21)*b*c^4*d^3
*f^m*x^5 + 3*(m^3 + 13*m^2 + 47*m + 35)*b*c^2*d^3*f^m*x^3 - (m^3 + 15*m^2 + 71*m + 105)*b*d^3*f^m*x)*x^m*log(c
*x + sqrt(c*x + 1)*sqrt(c*x - 1))/(m^4 + 16*m^3 + 86*m^2 + 176*m + 105) - integrate(((m^3 + 9*m^2 + 23*m + 15)
*b*c^7*d^3*f^m*x^7 - 3*(m^3 + 11*m^2 + 31*m + 21)*b*c^5*d^3*f^m*x^5 + 3*(m^3 + 13*m^2 + 47*m + 35)*b*c^3*d^3*f
^m*x^3 - (m^3 + 15*m^2 + 71*m + 105)*b*c*d^3*f^m*x)*x^m/((m^4 + 16*m^3 + 86*m^2 + 176*m + 105)*c^3*x^3 - (m^4
+ 16*m^3 + 86*m^2 + 176*m + 105)*c*x + ((m^4 + 16*m^3 + 86*m^2 + 176*m + 105)*c^2*x^2 - m^4 - 16*m^3 - 86*m^2
- 176*m - 105)*sqrt(c*x + 1)*sqrt(c*x - 1)), x) + integrate(((m^3 + 9*m^2 + 23*m + 15)*b*c^8*d^3*f^m*x^8 - 3*(
m^3 + 11*m^2 + 31*m + 21)*b*c^6*d^3*f^m*x^6 + 3*(m^3 + 13*m^2 + 47*m + 35)*b*c^4*d^3*f^m*x^4 - (m^3 + 15*m^2 +
 71*m + 105)*b*c^2*d^3*f^m*x^2)*x^m/((m^4 + 16*m^3 + 86*m^2 + 176*m + 105)*c^2*x^2 - m^4 - 16*m^3 - 86*m^2 - 1
76*m - 105), x)

Giac [F(-2)]

Exception generated. \[ \int (f x)^m \left (d-c^2 d x^2\right )^3 (a+b \text {arccosh}(c x)) \, dx=\text {Exception raised: TypeError} \]

[In]

integrate((f*x)^m*(-c^2*d*x^2+d)^3*(a+b*arccosh(c*x)),x, algorithm="giac")

[Out]

Exception raised: TypeError >> an error occurred running a Giac command:INPUT:sage2:=int(sage0,sageVARx):;OUTP
UT:sym2poly/r2sym(const gen & e,const index_m & i,const vecteur & l) Error: Bad Argument Value

Mupad [F(-1)]

Timed out. \[ \int (f x)^m \left (d-c^2 d x^2\right )^3 (a+b \text {arccosh}(c x)) \, dx=\int \left (a+b\,\mathrm {acosh}\left (c\,x\right )\right )\,{\left (d-c^2\,d\,x^2\right )}^3\,{\left (f\,x\right )}^m \,d x \]

[In]

int((a + b*acosh(c*x))*(d - c^2*d*x^2)^3*(f*x)^m,x)

[Out]

int((a + b*acosh(c*x))*(d - c^2*d*x^2)^3*(f*x)^m, x)